document.write( "Question 472730: Half of Henry's age added to 1/3 of Daisy's age is 11 years, 6 years from now the sum of their ages will be 40 years. How old is each? \n" ); document.write( "
Algebra.Com's Answer #324133 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Half of Henry's age added to 1/3 of Daisy's age is 11 years, \n" ); document.write( "6 years from now the sum of their ages will be 40 years. \n" ); document.write( " How old is each? \n" ); document.write( ": \n" ); document.write( "Let h = Henry's age \n" ); document.write( "Let d = Daisy's age \n" ); document.write( ": \n" ); document.write( "Write an equation for each statement: \n" ); document.write( ": \n" ); document.write( "\"Half of Henry's age added to 1/3 of Daisy's age is 11 years,\" \n" ); document.write( " \n" ); document.write( "Get rid of the fractions, multiply eq by 6, results: \n" ); document.write( "3h + 2d = 66 \n" ); document.write( ": \n" ); document.write( "\"6 years from now the sum of their ages will be 40 years.\" \n" ); document.write( "(h+6) + (d+6) = 40 \n" ); document.write( "h + d + 12 = 40 \n" ); document.write( "h + d = 40 - 12 \n" ); document.write( "h + d = 28 \n" ); document.write( "h = (28-d); we can use this for substitution \n" ); document.write( ": \n" ); document.write( "Replace h with (28-d) in the 1st equation \n" ); document.write( "3(28-d) + 2d = 66 \n" ); document.write( "84 - 3d + 2d = 66 \n" ); document.write( "-3d + 2d = 66 - 84 \n" ); document.write( "-d = -18 \n" ); document.write( "d = 18 yrs is Daisy's age \n" ); document.write( "then \n" ); document.write( "h = 28 - 18 \n" ); document.write( "h = 10 yrs is Henry's age \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check solutions in the 1st statement \n" ); document.write( "\"half of Henry's age added to 1/3 of Daisy's age is 11 years,\" \n" ); document.write( " \n" ); document.write( "5 + 6 = 11 \n" ); document.write( " \n" ); document.write( " |