document.write( "Question 472730: Half of Henry's age added to 1/3 of Daisy's age is 11 years, 6 years from now the sum of their ages will be 40 years. How old is each? \n" ); document.write( "
Algebra.Com's Answer #324133 by ankor@dixie-net.com(22740)\"\" \"About 
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Half of Henry's age added to 1/3 of Daisy's age is 11 years,
\n" ); document.write( "6 years from now the sum of their ages will be 40 years.
\n" ); document.write( " How old is each?
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\n" ); document.write( "Let h = Henry's age
\n" ); document.write( "Let d = Daisy's age
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\n" ); document.write( "Write an equation for each statement:
\n" ); document.write( ":
\n" ); document.write( "\"Half of Henry's age added to 1/3 of Daisy's age is 11 years,\"
\n" ); document.write( "\"1%2F2\"h + \"1%2F3\"d = 11
\n" ); document.write( "Get rid of the fractions, multiply eq by 6, results:
\n" ); document.write( "3h + 2d = 66
\n" ); document.write( ":
\n" ); document.write( "\"6 years from now the sum of their ages will be 40 years.\"
\n" ); document.write( "(h+6) + (d+6) = 40
\n" ); document.write( "h + d + 12 = 40
\n" ); document.write( "h + d = 40 - 12
\n" ); document.write( "h + d = 28
\n" ); document.write( "h = (28-d); we can use this for substitution
\n" ); document.write( ":
\n" ); document.write( "Replace h with (28-d) in the 1st equation
\n" ); document.write( "3(28-d) + 2d = 66
\n" ); document.write( "84 - 3d + 2d = 66
\n" ); document.write( "-3d + 2d = 66 - 84
\n" ); document.write( "-d = -18
\n" ); document.write( "d = 18 yrs is Daisy's age
\n" ); document.write( "then
\n" ); document.write( "h = 28 - 18
\n" ); document.write( "h = 10 yrs is Henry's age
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\n" ); document.write( "Check solutions in the 1st statement
\n" ); document.write( "\"half of Henry's age added to 1/3 of Daisy's age is 11 years,\"
\n" ); document.write( " \"1%2F2\"(10) + \"1%2F3\"(18) = 11
\n" ); document.write( "5 + 6 = 11
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