document.write( "Question 48949: A reservoir has two drain systems, large & small. Six large drains, on their own, can drain the reservoir in 12 hours. Three large pipes and 9 small pipes can drain it in 8 hours. How long will it take 5 small pipes to drain the reservoir. \n" ); document.write( "
Algebra.Com's Answer #32413 by venugopalramana(3286)![]() ![]() You can put this solution on YOUR website! more important is your statement that it is for 6 th.grade \n" ); document.write( "test and your mention on algebra.if it is for 6 th. grade ,they may \n" ); document.write( "not be exposed to algebra that much and hence my answer is of no use \n" ); document.write( ",if it is not ubderstood by the student.so let me give you below a \n" ); document.write( "method which needs only general maths principles. \n" ); document.write( "Question 48949: A reservoir has two drain systems, large & small. Six \n" ); document.write( "large drains, on their own, can drain the reservoir in 12 hours. Three \n" ); document.write( "large pipes and 9 small pipes can drain it in 8 hours. How long will \n" ); document.write( "it take 5 small pipes to drain the reservoir. \n" ); document.write( ": A reservoir has two drain systems, large & small. Six large drains, \n" ); document.write( "on their own, can drain the reservoir in 12 hours. Three large pipes \n" ); document.write( "and 9 small pipes can drain it in 8 hours. How long will it take 5 \n" ); document.write( "small pipes to drain the reservoir. \n" ); document.write( "6..................... large drains....... can drain in ...........12 \n" ); document.write( "hours.....................1 reservoir \n" ); document.write( "6........................ \n" ); document.write( "l.d.....................................................1.h..............................1/12 \n" ); document.write( "r \n" ); document.write( "1.........................l.d.....................................................1.h.................1/(12*6)=1/72 \n" ); document.write( "r \n" ); document.write( "----------------------------------------------------------------------------------------------------------------- \n" ); document.write( "3 l + 9 s........................................................................8 \n" ); document.write( "h.........................1 r \n" ); document.write( "3 l + 9 s.........................................................................1............................1/8 \n" ); document.write( "r \n" ); document.write( "but from above 1 large can drain in 1 hr 1/72 r...hence 3 l can drain \n" ); document.write( "in 1 hr..3/72=1/24 r \n" ); document.write( "hence 9 s can drain in 1 hr ....1/8 - 1/24 =2/24=1/12 r. \n" ); document.write( "9 s..................................................................................1............................1/12 \n" ); document.write( "r \n" ); document.write( "1 s..................................................................................1.............................1/108 \n" ); document.write( "r \n" ); document.write( "---------------------------------------------------------------------------------------------------------------------- \n" ); document.write( "from above 5 s will drain \n" ); document.write( " 5s................................................................................1....................5*1/108=5/108 \n" ); document.write( "r \n" ); document.write( "5 s will need .................................................................108/5 \n" ); document.write( "hrs.............1 r \n" ); document.write( "answer =21.6 hrs. \n" ); document.write( "hope this will be clear to your child.\r \n" ); document.write( "\n" ); document.write( "---------------------------------------------------------------------------- \n" ); document.write( "A reservoir has two drain systems, large & small. Six large drains, on their own, can drain the reservoir in 12 hours. Three large pipes and 9 small pipes can drain it in 8 hours. How long will it take 5 small pipes to drain the reservoir. \n" ); document.write( "LET EACH LARGE DRAIN CAPACITY =L \n" ); document.write( "LET EACH SMALL DRAIN CAPACITY=S \n" ); document.write( "SIX LARGE HAS=6L CAP. \n" ); document.write( "LET RESERVOIR VOLUME =R \n" ); document.write( "TIME TAKEN TO DRAIN WITH 6 LARGE=R/6L=12 HRS................ \n" ); document.write( "L=R/72..................I \n" ); document.write( "3 LARGE HAS =3L CAP. \n" ); document.write( "9 SMALL HAS =9S CAP. \n" ); document.write( "TOTAL DRAIN CAP.=3L+9S=3(L+3S) \n" ); document.write( "TIME TAKEN TO DRAIN=R/3(L+3S)=8...................... \n" ); document.write( "L+3S=R/24 \n" ); document.write( "3S=(R/24)-(R/72)=2R/72=R/36 \n" ); document.write( "S=R/108 \n" ); document.write( "5 SMALL CAP.=5S=5R/108 \n" ); document.write( "HENCE TIME NEEDED TO DRAIN =R/(5R/108)=108/5=21.6 HRS \n" ); document.write( " |