document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=6094>Question 6094</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me solve this equation:\r<BR>\n" );
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document.write( "4a - 2b[(4a + 3b)- 3c]- 5a\r<BR>\n" );
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document.write( "when a=  3<BR>\n" );
document.write( "     b= -2<BR>\n" );
document.write( "     c= -1 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #3241 by </B><A HREF=/tutors/aboutme.mpl?userid=guapa><B>guapa(62)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=guapa><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=3241\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Evaluate the parentheses first by substituting the variables by the given values. Start with the inner and continue.<BR>\n" );
document.write( "4a-2b[(4a+3b)-3c]-5a<BR>\n" );
document.write( "4a-2b{[4*3+3*(-2)]-3(-1)}-5a<BR>\n" );
document.write( "4a-2b[(12-6)+3]-5a<BR>\n" );
document.write( "4a-2b(9)-5a  Next we do the multiplication<BR>\n" );
document.write( "4a-2(-2)(9)-5a<BR>\n" );
document.write( "4a+36-5a Now substitute the remaining variables<BR>\n" );
document.write( "4*3+36-5*3<BR>\n" );
document.write( "12+36-15 = 33<BR>\n" );
document.write( "Hope this helps </SPAN>\n" );
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