document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=472662>Question 472662</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The half-life of Palladium-100 is 4 days. After 16 days a sample of Palaladium-100 has been reduce to a mass of 3 mg. \r<BR>\n" );
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document.write( "What was the initial mass of the sample?\r<BR>\n" );
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document.write( "What is the mass 7 weeks after the start? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #324088 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=324088\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The half-life of Palladium-100 is 4 days.<BR>\n" );
document.write( " After 16 days a sample of Palaladium-100 has been reduce to a mass of 3 mg.<BR>\n" );
document.write( "What was the initial mass of the sample?<BR>\n" );
document.write( "What is the mass 7 weeks after the start?<BR>\n" );
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document.write( "The half-life formula: A = Ao*2^(-t/h)<BR>\n" );
document.write( "Where<BR>\n" );
document.write( "A = resulting amt after t time<BR>\n" );
document.write( "Ao = initial amt<BR>\n" );
document.write( "t = time of decay<BR>\n" );
document.write( "h = half-life of substance<BR>\n" );
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document.write( "Find the initial amt<BR>\n" );
document.write( "Ao*2^(-16/4) = 3<BR>\n" );
document.write( "Ao*2^-4 = 3<BR>\n" );
document.write( ".0625*Ao = 3<BR>\n" );
document.write( "Ao = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=3%2F.0625 ALIGN=MIDDLE  ALT=\"3%2F.0625\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "Ao = 48 mg is the initial amt<BR>\n" );
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document.write( "Find the amt after 7*7 = 49 days<BR>\n" );
document.write( "A = 48*2^(-49/4)<BR>\n" );
document.write( "Enter above into a calc<BR>\n" );
document.write( "A = .00985 mg after 7 weeks </SPAN>\n" );
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