document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=472729>Question 472729</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Half of henry's age added to 1/3 of Daisy's age is 11 years. Six years from now, the sum of their ages will be 40 years. How old is each? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #324065 by </B><A HREF=/tutors/aboutme.mpl?userid=monika_p><B>monika_p(71)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=monika_p><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=324065\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a-Henry's age<BR>\n" );
document.write( "b-Daisy's age\r<BR>\n" );
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document.write( "From information you have you can write 2 equations<BR>\n" );
document.write( "1/2a+1/3b=11<BR>\n" );
document.write( "(a+6)+(b+6)=40<BR>\n" );
document.write( "Solve it as system of 2 equations<BR>\n" );
document.write( "from second equation find a<BR>\n" );
document.write( "a=40-12-b <BR>\n" );
document.write( "a= 28-b<BR>\n" );
document.write( " put it in first equation and find b<BR>\n" );
document.write( "1/2(28-b)+1/3b=11<BR>\n" );
document.write( "14-1/2b+1/3b=11<BR>\n" );
document.write( "-3/6b+2/6b=-3<BR>\n" );
document.write( "-1/6b=-3<BR>\n" );
document.write( "b=18 then a= 28-18=10<BR>\n" );
document.write( " </SPAN>\n" );
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