document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=472611>Question 472611</A>: <I><SPAN STYLE=\"word-break: break-all;\"> what is the area of a isosileas triangel 12m by 12m </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #324036 by </B><A HREF=/tutors/aboutme.mpl?userid=richard1234><B>richard1234(7193)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richard1234><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richard1234><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=324036\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> First of all, it's spelled \"isosceles.\" Second of all, the dimensions you provided do not uniquely determine an isosceles triangle, so the area cannot be determined. The area would be 12*12*sin(x)/2 = 72 sin x, where x is the angle in between the 12 m sides. </SPAN>\n" );
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