document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=472703>Question 472703</A>: <I><SPAN STYLE=\"word-break: break-all;\"> x=by+cz<BR>\n" );
document.write( "y=cz+ax<BR>\n" );
document.write( "z=ax+by<BR>\n" );
document.write( "prove a/1+a + b/1+b + c/1+c = 1\r<BR>\n" );
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document.write( "pls help with solution...thanks </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #324031 by </B><A HREF=/tutors/aboutme.mpl?userid=richard1234><B>richard1234(7193)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richard1234><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richard1234><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=324031\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Adding all three of our given statements we obtain x+y+z = 2ax + 2by + 2cz. Matching the x,y,z coefficients, we get 2a = 1, 2b = 1, 2c = 1, so a,b,c = 1/2. Replacing 1/2 into a/(1+a) + b/(1+b) + c/(1+c) yields a sum of 1. </SPAN>\n" );
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