document.write( "Question 472651: How would i set up a system of equations for \"The length of Sally's garden is 4 meters greater than 3 times the width. The perimeter of her garden is 72 meters.\" And how would i find the dimensions.\r
\n" ); document.write( "\n" ); document.write( "I do know that to find perimeter you use \"+P=2l%2B2w+\". I also defined my variables as length = x and width = y. So far if i am doing it correctly I have \"+3y%2B4=x+\" to represent the length if 4 meters greater than 3 times the width.
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Algebra.Com's Answer #324008 by richard1234(7193)\"\" \"About 
You can put this solution on YOUR website!
Good start. However you haven't used the fact that the perimeter is 72. Since the length is x and width is y, we can say that 2(x+y) = 72 --> x+y = 36. Now you have a system of two equations that should be easy to solve for. \n" ); document.write( "
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