document.write( "Question 6093: How would you complete each table of values?\r
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document.write( "Problems:
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document.write( "a. y/5 = x/2 - 5
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document.write( " x y
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document.write( " 0
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document.write( " 1
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document.write( " 2
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document.write( "-1
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document.write( "-2
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document.write( "b. x = y/3 + 7\r
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document.write( " x y
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document.write( " 0
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document.write( " 2
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document.write( " 4
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document.write( "-3
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document.write( "-4 \r
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document.write( "Here are my answers (which were wrong)\r
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document.write( "a. y/5 = x/2 - 5\r
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document.write( " x y
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document.write( " 0 3
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document.write( " 1 4
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document.write( " 2 3
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document.write( "-1 -6
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document.write( "-2 -7\r
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document.write( " b. x = y/3 + 7\r
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document.write( " x y
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document.write( " 0 -7
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document.write( " 2 5
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document.write( " 4 4
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document.write( " -3 -4
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document.write( " -4 -3\r
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document.write( "Thanks
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document.write( "TSJ
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Algebra.Com's Answer #3240 by Abbey(339)![]() ![]() ![]() You can put this solution on YOUR website! I would just plug the given values into the equations and solve for the variable., but first i would get rid of the denominator on the y term: \n" ); document.write( "multiply by 5: \n" ); document.write( "a. y/5 = x/2 - 5 \n" ); document.write( "y=5x/2-25 \n" ); document.write( "y=5(0)/2-25 = -25 \n" ); document.write( "y=5(1)/2-25 = -22 1/2 \n" ); document.write( "y=5(2)/2-25 = -20 \n" ); document.write( "y=5(-1)/2-25 = -27 1/2 \n" ); document.write( "y=5(-2)/2-25 = -30\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "multiply by 3: \n" ); document.write( "b. x = y/3 + 7 \n" ); document.write( "then subtract 7 from both sides: \n" ); document.write( "3x=y+7 \n" ); document.write( "3x-7=y \n" ); document.write( "3( 0 )-7=-7 \n" ); document.write( "3( 2 )-7=-1 \n" ); document.write( "3( 4 )-7=5 \n" ); document.write( "3(-3 )-7=-16 \n" ); document.write( "3(-4 )-7=-19\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |