document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=472558>Question 472558</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If the mean of a normal distribution is 25, and the standard deviation is 1, it is highly unlikely that a value in the data is 24. <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #323998 by </B><A HREF=/tutors/aboutme.mpl?userid=robertb><B>robertb(5830)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=robertb><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=robertb><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=323998\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Your problem needs restatement. When you are dealing with CONTINUOUS probability function (or pdf), in this case a normal distribution, it doesn't really make sense to ask for the probability of occurence of a PARTICULAR value of the random variable.  It will always be ZERO.  Probability for continuous random variables always goes one way or the other, and it is always considered cumulatively. (Say \"how likely is it for a value to be LESS THAN OR EQUAL TO 24?\", or the other way.)\r<BR>\n" );
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document.write( "So a direct answer to your question is, TRUE, it is highly unlikely, because its probability is 0. </SPAN>\n" );
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