document.write( "Question 472504: PLEASE HELLPP!!! Given p is false, q is true, and r is false, find the truth value of the statement (~p ↔ ~q) ~r.\r
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Algebra.Com's Answer #323956 by MathLover1(20849)![]() ![]() You can put this solution on YOUR website! If p is true, then ~p is false (since ~p is the opposite of p).\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Remember that \"^\" means \"and\". The statement p ^ q is only true if BOTH p AND q are true (hence the \"and\"). Since ~p is false, we automatically know that ~p ^ q is false (q doesn't have to be factored in at all).\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Finally, remember that p <-> q is only true if the truth values for p and q are the same. So if p and q are both true, or both false, then p <-> q is true. Think of this as an \"equals\" (ie p = q). Because r is true, ~r is false. Since ~p ^ q is false as well, ~p ^ q and ~r have the same truth values. So (~p ^ q) <-> ~r is true. \r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Here's one way you could write all this out:\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(~p ^ q) <-> ~r\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(~T ^ F) <-> ~T\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(F ^ F) <-> F\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "F <-> F\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "T\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Answer by jim_thompson5910\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |