document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=472442>Question 472442</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I would like help on what steps do I have to take to solve: (2/3)x-5=x-3.   I am not sure where to begin. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #323948 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=323948\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (2/3)x-5=x-3<BR>\n" );
document.write( "Add 5<BR>\n" );
document.write( "(2/3)x = x + 2<BR>\n" );
document.write( "Multiply by 3<BR>\n" );
document.write( "2x = 3x + 6<BR>\n" );
document.write( "subtract 3x<BR>\n" );
document.write( "-x = 6<BR>\n" );
document.write( "x = -6<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );