document.write( "Question 472447: In an isosceles triangle, the length of each leg exceeds twice the base by 2 cm. The perimeter is 24. How long is each leg? \n" ); document.write( "
Algebra.Com's Answer #323932 by nerdybill(7384)\"\" \"About 
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In an isosceles triangle, the length of each leg exceeds twice the base by 2 cm. The perimeter is 24. How long is each leg?
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\n" ); document.write( "Draw a diagram of the problem, it'll help you see the solution.
\n" ); document.write( "Let b = length of base
\n" ); document.write( "then
\n" ); document.write( "2b+2 = length of leg
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\n" ); document.write( "2(2b+2) + b = 24
\n" ); document.write( "4b+4 + b = 24
\n" ); document.write( "5b = 20
\n" ); document.write( "b = 4 cm (base)
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\n" ); document.write( "length of the two legs:
\n" ); document.write( "2b+2 = 2(4)+2 = 10 cm \n" ); document.write( "
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