document.write( "Question 472433: The initial population of a town is 127,866 and it grows with a doubling time of 12 years. What will the population be in 33 years? \n" ); document.write( "
Algebra.Com's Answer #323915 by nerdybill(7384)![]() ![]() You can put this solution on YOUR website! The initial population of a town is 127,866 and it grows with a doubling time of 12 years. What will the population be in 33 years? \n" ); document.write( ". \n" ); document.write( "assuming exponential growth: \n" ); document.write( "a = pe^(rt) \n" ); document.write( "first, we need to find r (rate of growth) \n" ); document.write( "2(127866) = 127866e^(r*12) \n" ); document.write( "2 = e^(r*12) \n" ); document.write( "ln(2) = 12r \n" ); document.write( "ln(2)/12 = r \n" ); document.write( ". \n" ); document.write( "Our general formula: \n" ); document.write( "a = 127866e^(ln(2)/12 * t) \n" ); document.write( ". \n" ); document.write( "subsitute 33 for t: \n" ); document.write( "a = 127866e^(ln(2)/12 * 33) \n" ); document.write( "a = 127866e^(1.9062) \n" ); document.write( "a = 127866(6.7272) \n" ); document.write( "a = 860176\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |