document.write( "Question 472433: The initial population of a town is 127,866 and it grows with a doubling time of 12 years. What will the population be in 33 years? \n" ); document.write( "
Algebra.Com's Answer #323915 by nerdybill(7384)\"\" \"About 
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The initial population of a town is 127,866 and it grows with a doubling time of 12 years. What will the population be in 33 years?
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\n" ); document.write( "assuming exponential growth:
\n" ); document.write( "a = pe^(rt)
\n" ); document.write( "first, we need to find r (rate of growth)
\n" ); document.write( "2(127866) = 127866e^(r*12)
\n" ); document.write( "2 = e^(r*12)
\n" ); document.write( "ln(2) = 12r
\n" ); document.write( "ln(2)/12 = r
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\n" ); document.write( "Our general formula:
\n" ); document.write( "a = 127866e^(ln(2)/12 * t)
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\n" ); document.write( "subsitute 33 for t:
\n" ); document.write( "a = 127866e^(ln(2)/12 * 33)
\n" ); document.write( "a = 127866e^(1.9062)
\n" ); document.write( "a = 127866(6.7272)
\n" ); document.write( "a = 860176\r
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