document.write( "Question 472240: Moa invested $80000,part at 4% and the rest at 2%.Find the amount invested at each rate if the annual income from the two investmets is $2500. \n" ); document.write( "
Algebra.Com's Answer #323813 by mananth(16946)\"\" \"About 
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x+y80000 ------------------------1
\n" ); document.write( "4.00%x+ 2.00%y=$2,500.00
\n" ); document.write( "Multiply by 100
\n" ); document.write( "4x+2y= $250,000.00 --------2
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\n" ); document.write( "Multiply (1) by -4
\n" ); document.write( "we get
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\n" ); document.write( "-4x-4y= -320000.00
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\n" ); document.write( "Add this to (2)
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\n" ); document.write( "-2y= -$70,000.00
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\n" ); document.write( "divide by -2
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\n" ); document.write( "y=$35,000.00 investment at 2.00%
\n" ); document.write( "Balance $45,000.00 investment at 4.00%\r
\n" ); document.write( "\n" ); document.write( "CHECK Interest
\n" ); document.write( "$45,000.00 $1,800.00
\n" ); document.write( "$35,000.00 $700.00
\n" ); document.write( "Total $2,500.00
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