document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=472087>Question 472087</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the sqroot of (3x+10)^2= (5-2x)^2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #323755 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=323755\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3x+10=(5-2x)^2 remove the square sign from the left side.<BR>\n" );
document.write( "...=4x^2-20x+25<BR>\n" );
document.write( "4x^2-23x+15=0<BR>\n" );
document.write( "4*15=60; The 2 factors of 60 whose sum is -23 are -3 and -20.<BR>\n" );
document.write( "4x^2-3x-20x+15=0<BR>\n" );
document.write( "x(4x-3)-5(4x-3)=0 factoring by grouping.<BR>\n" );
document.write( "(x-5)(4x-3)=0<BR>\n" );
document.write( "x=5, x=3/4<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Ed </SPAN>\n" );
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