document.write( "Question 472135: 13+squre root 2x-3>15
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Algebra.Com's Answer #323742 by jorel1380(3719) $\"\"$ $\"About$

You can put this solution on YOUR website!
$\"13%2Bsqrt%282x-3%29%3E15\"$
\n" ); document.write( " $\"sqrt%282x-3%29%3E2\"$
\n" ); document.write( " $\"2x-3%3E4\"$
\n" ); document.write( " $\"2x%3E7\"$
\n" ); document.write( " $\"x%3E7%2F2\"$ .. \n" ); document.write( "

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