document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=471851>Question 471851</A>: <I><SPAN STYLE=\"word-break: break-all;\"> complete the conjecture based on the pattern you observe in the specific case.\r<BR>\n" );
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document.write( "Conjecture: For any 2 numbers a and b, the product of (a+b) and (a-b) is always equal to ________ ?<BR>\n" );
document.write( "(2+1)(2-1) = 3= 2^2 - 1^2<BR>\n" );
document.write( "(3+2)(3-2) = 5= 3^2 - 2^2<BR>\n" );
document.write( "(4+2)(4-2) = 12= 4^2 - 2^2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #323651 by </B><A HREF=/tutors/aboutme.mpl?userid=richard1234><B>richard1234(7193)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richard1234><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richard1234><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=323651\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a^2 - b^2. We do not need to call it a conjecture anymore since it can easily be proven. </SPAN>\n" );
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