document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=48862>Question 48862</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/1592009425/algebrahomeworkh>albrega II</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> The sum of the digits of a two digit no. is 12. If the digits are reversed, the new no. is 15 more than twice the original no. Find the orginal no.\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #32365 by </B><A HREF=/tutors/aboutme.mpl?userid=Paul><B>Paul(988)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Paul><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=32365\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> \let x be the 10 digit and let y be the one digit<BR>\n" );
document.write( "original number = 10x+y<BR>\n" );
document.write( "reversed = 10y+x<BR>\n" );
document.write( "x+y=12<BR>\n" );
document.write( "y=12-x (subsitution)\r<BR>\n" );
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document.write( "10y+x=15+10x+y<BR>\n" );
document.write( "10(12-x)+x=10x+12-x<BR>\n" );
document.write( "120-10x+x-9x=12<BR>\n" );
document.write( "-18x=-108<BR>\n" );
document.write( "x=6<BR>\n" );
document.write( "y=12-6<BR>\n" );
document.write( "y=6<BR>\n" );
document.write( "Hence, the number is 66<BR>\n" );
document.write( "Paul. </SPAN>\n" );
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