document.write( "Question 471804: A projectile is fired from a cliff 100 feet above the water at an inclination of 45° to the horizontal, with a muzzle velocity of 170 feet per second. The height h of the projectile above the water is given by
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document.write( "where x is the horizontal distance of the projectile from the base of the cliff. How far from the base of the cliff is the height of the projectile a maximum? \r
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document.write( "A. 225.78 ft
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document.write( "B. 451.56 ft
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document.write( "C. 325.78 ft
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document.write( "D. 777.34 ft \r
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Algebra.Com's Answer #323636 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! A projectile is fired from a cliff 100 feet above the water at an inclination of 45° to the horizontal, with a muzzle velocity of 170 feet per second. The height h of the projectile above the water is given by \n" ); document.write( " \n" ); document.write( "where x is the horizontal distance of the projectile from the base of the cliff. How far from the base of the cliff is the height of the projectile a maximum? \n" ); document.write( ": \n" ); document.write( "Convert the coefficient of x^2 to a more manageable value \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( "h(x) = -.001107x^2 + x + 100 \n" ); document.write( ": \n" ); document.write( "find the axis of symmetry, x = -b/(2a), in this equation a=-.001107, b=1 \n" ); document.write( "x = \n" ); document.write( "x = +451.6 ft from the base of the cliff, it will be at max height\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |