document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=48865>Question 48865</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve\r<BR>\n" );
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document.write( "9x^2 - 12x - 5\r<BR>\n" );
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document.write( "Thank You\r<BR>\n" );
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document.write( "  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #32362 by </B><A HREF=/tutors/aboutme.mpl?userid=Nate><B>Nate(3500)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Nate><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=32362\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I take it that the expression you showed is equal to zero:<BR>\n" );
document.write( "9x^2 - 12x - 5 = 0 find factors of 9 * -5 = -45 that sum to -12 ~~~> -15,3<BR>\n" );
document.write( "9x^2 - 15x + 3x - 5 = 0<BR>\n" );
document.write( "3x(3x - 5) + 1(3x - 5) = 0<BR>\n" );
document.write( "(3x + 1)(3x - 5) = 0<BR>\n" );
document.write( "3x + 1 = 0<BR>\n" );
document.write( "3x = -1<BR>\n" );
document.write( "x = -1/3<BR>\n" );
document.write( "and<BR>\n" );
document.write( "3x - 5 = 0<BR>\n" );
document.write( "3x = 5<BR>\n" );
document.write( "x = 5/3 </SPAN>\n" );
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