document.write( "Question 471866: Sally has a glass that is 1/3 filled with syrup. Bob has a glass that is 1/4 filled with syrup but Bob's glass holds twice as much as Sally's. If they were to fill the rest of their glasses with milk, then mix them together, what part of the combine mixture would be syrup.
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Algebra.Com's Answer #323597 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

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Sally has a glass that is 1/3 filled with syrup.
\n" ); document.write( " Bob has a glass that is 1/4 filled with syrup but Bob's glass holds twice as much as Sally's.
\n" ); document.write( "If they were to fill the rest of their glasses with milk, then mix them together, what part of the combine mixture would be syrup.
\n" ); document.write( ":
\n" ); document.write( "let x = amt to fill Sally's glass
\n" ); document.write( "and
\n" ); document.write( "2x = amt to fill Bob's glass
\n" ); document.write( "then
\n" ); document.write( "total amt when mixed together = 3x
\n" ); document.write( ":
\n" ); document.write( "Sally's syrup = $\"1%2F3\"$ x
\n" ); document.write( "Bob's syrup = $\"1%2F4\"$ (2x) = $\"2%2F4\"$ x = $\"1%2F2\"$ x
\n" ); document.write( ":
\n" ); document.write( " $\"1%2F3\"$ x + $\"1%2F2\"$ x =
\n" ); document.write( " $\"2%2F6\"$ x + $\"3%2F6\"$ x = $\"5%2F6\"$ x; amt of syrup when mixed together
\n" ); document.write( "Find what part 3x is $\"5%2F6\"$ x?
\n" ); document.write( ":
\n" ); document.write( "The x's cancel so we have:
\n" ); document.write( " $\"%285%2F6%29%2F3\"$ = $\"5%2F6\"$ * $\"1%2F3\"$ = $\"5%2F18\"$ of the total mixture is syrup \n" ); document.write( "

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