document.write( "Question 471784: The weight of a miniature Tootsie Roll is normally distributed with a mean of 3.30 grams and standard deviation of 0.13 grams.
\n" ); document.write( " (a) Within what weight range will the middle 95 percent of all
\n" ); document.write( "miniature Tootsie Rolls fall?
\n" ); document.write( " (b) What is the probability that a randomly chosen miniature
\n" ); document.write( "Tootsie Roll will weigh more than 3.50 grams?
\n" ); document.write( "c) What is the probability that a randomly chosen miniature
\n" ); document.write( "Tootsie Roll will weigh between 3.25 and 3.45 grams?
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Algebra.Com's Answer #323553 by ewatrrr(24785)\"\" \"About 
You can put this solution on YOUR website!
 
\n" ); document.write( "Hi,
\n" ); document.write( "The weight of a miniature Tootsie Roll is normally distributed with a mean of 3.30 grams and standard deviation of 0.13 grams
\n" ); document.write( "(a) Within what weight range will the middle 95 percent of all miniature Tootsie Rolls fall?
\n" ); document.write( "Within 2 sd of the mean: sd=.13 range will be: 3.04 to 3.56\r
\n" ); document.write( "\n" ); document.write( "P(x>3.50)
\n" ); document.write( " |z = (3.50-3.30)/.13 = 1.5385
\n" ); document.write( " P(x > 3.50)= 1 -P( z ≤ 1.5385) = 1- .938 = .062\r
\n" ); document.write( "\n" ); document.write( "P(between 3.25 abd 3.45)
\n" ); document.write( "|z = (3.25-3.30)/.13 = -.3846 and z = (3.45-3.30)/.13 = 1.1538
\n" ); document.write( "P(between 3.25 abd 3.45) = P(z ≤ 1.1538)- P(z ≤ -.3846) = .8757 - .3503 = .5254 \n" ); document.write( "
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