document.write( "Question 471820: During the first part of a trip, a canoiest travels 100miles at a certain speed. The canoiest travels 45miles on the second part of the trip at a speed 5mph slower. The total time for the trip is 3hrs. What was the speed on each part of the trip? \n" ); document.write( "
Algebra.Com's Answer #323552 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! During the first part of a trip, a canoiest travels 100 miles at a certain speed. \n" ); document.write( "---------------- \n" ); document.write( "The canoiest travels 45miles on the second part of the trip at a speed 5mph slower. \n" ); document.write( "----------- \n" ); document.write( "The total time for the trip is 3hrs. \n" ); document.write( "---------------- \n" ); document.write( "What was the speed on each part of the trip? \n" ); document.write( "=== \n" ); document.write( "1st Part DATA: \n" ); document.write( "distance = 100 miles ; rate = r mph ; time = 100/r hrs \n" ); document.write( "---------- \n" ); document.write( "2nd Part DATA: \n" ); document.write( "distance = 45 miles : rate = r-5 mph ; time = 45/(r-5) hrs \n" ); document.write( "--------- \n" ); document.write( "Equation: \n" ); document.write( "time + time = 3 hrs \n" ); document.write( "100/r + 45/(r-5) = 3 hrs \n" ); document.write( "--- \n" ); document.write( "100(r-5) + 45r + 3r(r-5) \n" ); document.write( "--- \n" ); document.write( "145r - 500 = 3r^2-15r \n" ); document.write( "--- \n" ); document.write( "3r^2 -160r + 500 = 0 \n" ); document.write( "--- \n" ); document.write( "I graphed the quadratic and found \n" ); document.write( "a realistic solution at r = 50 mph (rate on 1st part of trip) \n" ); document.write( "--- \n" ); document.write( "Then r-5 = 45 mph (rate on 2nd part of trip) \n" ); document.write( "================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "==================\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |