document.write( "Question 471776: solve cosx(sinx-1/2)=0 [0-2/pi] \n" ); document.write( "
Algebra.Com's Answer #323533 by oadeshina(1)![]() ![]() You can put this solution on YOUR website! cosx*(sinx-1\2)=0 \n" ); document.write( "either cosx=0 or sinx-1\2=0 \n" ); document.write( "if sinx-1\2=0, then sinx=1\2,sinx=0.5, x=sin^1*0.5 \n" ); document.write( "then x=30. thanks \n" ); document.write( " \n" ); document.write( " |