document.write( "Question 471776: solve cosx(sinx-1/2)=0 [0-2/pi] \n" ); document.write( "

Algebra.Com's Answer #323529 by Tatiana_Stebko(1539) $\"\"$ $\"About$

You can put this solution on YOUR website!
$\"cosx%28sinx-1%2F2%29=0\"$
\n" ); document.write( " $\"cosx=0\"$ or $\"sinx-1%2F2=0\"$
\n" ); document.write( " $\"x=pi%2F2\"$ or $\"sin+x=1%2F2\"$
\n" ); document.write( " $\"x1=pi%2F2\"$ or $\"x2=pi%2F6\"$ \n" ); document.write( "

\n" );