document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=48859>Question 48859</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Good evening. i would like to ask you to help me with this problem<BR>\n" );
document.write( "              i cannot work out, please would you help me?\r<BR>\n" );
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document.write( " (1) John makes business trip from his house to Portland in 2 hours. Three hours later, he returns home in traffic at 20mph less than his speed going. If John is gone a total of 8 hours, how fast did he travel to Portland. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #32352 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=32352\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> DISTANCE=RATE*TIME & T=D/R OR  2=D/R OR D=2R GOING TO PORTLAND & (8-2-3)=D/(R-20) OR 3=D/(R-20) OR D=3R-60 RETURNING FROM PORTLAND THUS 2R=3R-60 OR R=60 MPH <BR>\n" );
document.write( "ON THE TRIP TO PORTLAND </SPAN>\n" );
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