document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=48858>Question 48858</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Good evening.I would like to ask you about this two problem, i try alday i cannot get the answer. Please help in this problem.<BR>\n" );
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document.write( " (1) A parking meter takes only dimes and quarters. IF the meter held $7.55 at the end of one day, and the number of dimes was 8 more than 20 times the number of quarters, then the total number of coins is how much?<BR>\n" );
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document.write( "  (2) The number of dimes in Gina's coin collection is 4 less than the number of nickels, and then number of quarters is 3 times the number of dimes. If the value of her collection is $7.40, how many nickels does she have?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #32351 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=32351\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 755=(8+20q)10+25q or 755=80+200q+25q or 755-80=225q or 675=225q or q=3 thus\r<BR>\n" );
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document.write( "there are 3 quarters & 20*3+8=68 dimes thus 3*25+68*10=775 or 75+680=775 or \r<BR>\n" );
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document.write( "775=775  </SPAN>\n" );
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