document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=6090>Question 6090</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In the period of a year, an investor lost twice as much as he gained. If he originally had $10,000 and now has $8,000, what amount did he gain abd what did he lose? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #3235 by </B><A HREF=/tutors/aboutme.mpl?userid=Abbey><B>Abbey(339)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Abbey><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=3235\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let x = the amount gained<BR>\n" );
document.write( "let -2x = the amount lost<BR>\n" );
document.write( "because we are retracing what happened to the money we have to work in the opposite direction:  the gain will be subtracted and the loss will be added back in:<BR>\n" );
document.write( "the amount he has now (8000)  minus the gain, plus the loss will equal 10000<BR>\n" );
document.write( "8000-x+2x=10000<BR>\n" );
document.write( "subtract 8000 from both sides<BR>\n" );
document.write( "x=2000\r<BR>\n" );
document.write( "\n" );
document.write( "so he gained 2000 and lost twice that or 4000.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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