document.write( "Question 48853: Please help with this problem. I have been doing fine with consecutive integer problems until the \"squares\" part was added.\r
\n" ); document.write( "\n" ); document.write( "Q: The sum of the squares of two consecutive odd integers decreased by the product of the integers is the same as 67. \r
\n" ); document.write( "\n" ); document.write( "I have been setting it up like this, but think I may be starting wrong since I don't seem to get answers that make sense\r
\n" ); document.write( "\n" ); document.write( " x^2+(x+2)^2 - x(x+2) = 67 \n" ); document.write( "
Algebra.Com's Answer #32348 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
Q: The sum of the squares of two consecutive odd integers decreased by the product of the integers is the same as 67. \r
\n" ); document.write( "\n" ); document.write( "Comment:
\n" ); document.write( "Even numbers must be symbolized as multiples of two, e.g. 2x, 2(x+1), etc.
\n" ); document.write( "Odd numbers are always 1 more than some even number. They must be symbolized
\n" ); document.write( "as 2x+1 or 2x+3 etc.
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\n" ); document.write( "So for your problem
\n" ); document.write( "Two consecutive odd integers are
\n" ); document.write( "1st: 2x+1
\n" ); document.write( "2nd: 2x+3
\n" ); document.write( "EQUATION:
\n" ); document.write( "(2x+1)^2+(2x+3)^2-(2x+1)(2x+3)=67
\n" ); document.write( "Solve this equation for x.
\n" ); document.write( "Then find 2x+1 and 2x+3
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H. \n" ); document.write( "
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