document.write( "Question 471539: given any three consecutive integers prove that the product of the first and third number is one less than the squareof the middle one \n" ); document.write( "

Algebra.Com's Answer #323426 by richard1234(7193) $\"\"$ $\"About$

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Let x, x+1, x+2 be the three integers. The product of the first and third number is x(x+2) = x^2 + 2x. The square of the middle one is (x+1)^2 = x^2 + 2x + 1. Hence the product of the first and third numbers is one less than the square of the middle one. \n" ); document.write( "

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