document.write( "Question 471491: A motorboat maintained a constant speed of 11 miles per hour relative to water in Goin 30 miles upstream and then returning. The total time for the trip was 5.5 hours. Use this information to find the speed of the current\r
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Algebra.Com's Answer #323421 by ankor@dixie-net.com(22740)\"\" \"About 
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A motorboat maintained a constant speed of 11 miles per hour relative to water in Going 30 miles upstream and then returning.
\n" ); document.write( " The total time for the trip was 5.5 hours.
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\n" ); document.write( "Let c = speed of the current
\n" ); document.write( "then
\n" ); document.write( "(11+c) = speed downstream relative to land
\n" ); document.write( "and
\n" ); document.write( "(11-c) = speed upstream relative to the land
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\n" ); document.write( "Write a time equation: time = dist/speed
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\n" ); document.write( "time upstream + time downstream = 5.5 hrs
\n" ); document.write( "\"30%2F%28%2811-c%29%29\" + \"30%2F%28%2811%2Bc%29%29\" = 5.5
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\n" ); document.write( "Multiply by (11-c)(11+c), results:
\n" ); document.write( "30(11+c) + 30(11-c) = 5.5(11+c)(11-c)
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\n" ); document.write( "330 + 30c + 330 - 30c = 5.5(121 - 11c + 11c - c^2)
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\n" ); document.write( "660 = 5.5(121 - c^2)
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\n" ); document.write( "660 = 665.5 - 5.5c^2
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\n" ); document.write( "5.5c^2 = 665.5 - 660
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\n" ); document.write( "5.5c^2 = 5.5
\n" ); document.write( "Divide both sides by 5.5
\n" ); document.write( "c^2 = 1
\n" ); document.write( "c = 1 mph is the current
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\n" ); document.write( "See if this is true; find the times both ways
\n" ); document.write( "downstream: 30/12 = 2.5 hrs
\n" ); document.write( "up-stream: 30/10 = 3.0 hrs
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\n" ); document.write( "total time: 5.5 hrs
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