document.write( "Question 471498: form a four-digit numbers using the set of digits {0, 1, 2, 3, 4, 5, 6}. If one four-digit number is chosen at random from all those that can be made, find the probability that the one chosen does not end with a 3. \n" ); document.write( "
Algebra.Com's Answer #323374 by Edwin McCravy(20055)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( " form a four-digit numbers using the set of digits {0, 1, 2, 3, 4, 5, 6}. If one four-digit number is chosen at random from all those that can be made, find the probability that the one chosen does not end with a 3.
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document.write( "First we calculate the numerator of the probability:\r\n" );
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document.write( "We can choose the digits in any order.  So we choose the most restrictive digit first.  \r\n" );
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document.write( "We can choose the fourth digit any of 6 ways 0,1,2,4,5,or 6, just not 3.\r\n" );
document.write( "We can choose the first digit any of 6 ways (because we can choose the 3 for the first digit)\r\n" );
document.write( "We can choose the second digit any of 5 ways\r\n" );
document.write( "We can choose the third digit any of 4 ways.\r\n" );
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document.write( "So the numerator of the probability is 6*6*5*4\r\n" );
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document.write( "Next we calculate the denominator of the probability:\r\n" );
document.write( "There is no restriction here, so we'll just choose them left to right \r\n" );
document.write( "We can choose the first digit any of 7 ways\r\n" );
document.write( "We can choose the second digit any of 6 ways\r\n" );
document.write( "We can choose the third digit any of 5 ways.\r\n" );
document.write( "We can choose the fourth digit any of 4 ways\r\n" );
document.write( "So the denominator of the probability is 7*6*5*4\r\n" );
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document.write( "The probability is then \r\n" );
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document.write( "Edwin
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