document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=48787>Question 48787</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve by addition.\r<BR>\n" );
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document.write( "-3x + y = 3<BR>\n" );
document.write( "2x - 3y = 5 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #32336 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=32336\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> MULTIPLY EQUATION #1 BY 3 WE GET -9X+3Y=9 NOW ADD THIS TO EQUATION #2 WE GET\r<BR>\n" );
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document.write( "2X-3Y=5<BR>\n" );
document.write( "-9X+3Y=9<BR>\n" );
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document.write( "-7X=14 OR X=14/-7 OR X=-2 \r<BR>\n" );
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document.write( "THEN 2(-2)-3Y=5 OR -4-3Y=5 OR -3Y=9 OR Y=9/-3 OR Y=-3 </SPAN>\n" );
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