document.write( "Question 471414: Use x and y to solve the following problem. Solve with a system of two equations. A candy mix sells for $1.10 per pound. If the mix is composed of two kinds of candy, one worth $.90 per pound and the other worth $1.50 per pound, how many pounds of each would be in a 60 pound mixture? \n" ); document.write( "
Algebra.Com's Answer #323319 by mananth(16946)![]() ![]() You can put this solution on YOUR website! candy I = x lb \n" ); document.write( "candy II= y lb \n" ); document.write( "x+y=60\r \n" ); document.write( "\n" ); document.write( "0.9x+1.5y=60*1.10\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "1 x + 1 y = 60 .............1 \n" ); document.write( "0.9 x + 1.5 y = 66 .............2 \n" ); document.write( " \n" ); document.write( "multiply (1)by -1.5 \n" ); document.write( "Multiply (2) by 1 \n" ); document.write( "-1.5 x -1.5 y = -90 \n" ); document.write( "0.9 x 1.5 y = 66 \n" ); document.write( "Add the two equations \n" ); document.write( "-0.6 x = -24 \n" ); document.write( "/ -0.6 \n" ); document.write( "x = 40 lb \n" ); document.write( "plug value of x in (1) \n" ); document.write( "1 x + 1 y = 60 \n" ); document.write( "40 + 1 y = 60 \n" ); document.write( " 1 y = 60 -40 \n" ); document.write( " 1 y = 20 \n" ); document.write( " y = 20 lb \r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |