document.write( "Question 48744This question is from textbook College Algebra
\n" ); document.write( ": Write the sum without using sigma notation:\r
\n" ); document.write( "\n" ); document.write( "n over (capital sigma)j=1(under) (-1)^j+1 x^j\r
\n" ); document.write( "\n" ); document.write( "Thank you very much!
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Algebra.Com's Answer #32331 by kev82(151)\"\" \"About 
You can put this solution on YOUR website!
Hi,\r
\n" ); document.write( "\n" ); document.write( "So we need to find a formula for \r
\n" ); document.write( "\n" ); document.write( "To figure out what's actually happenning, lets write out a few terms (I'm only going to work with even N for now)\r
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\n" ); document.write( "\n" ); document.write( "Or splitting this into two sequences.\r
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\n" ); document.write( "\n" ); document.write( "You should be able to see that the first sequence is just a factor of -x different from the first.\r
\n" ); document.write( "\n" ); document.write( "The sequence clearly has N/2 terms(remember I'm assuming N even at moment)\r
\n" ); document.write( "\n" ); document.write( "Using the formula for a geometric series (1-x^n)/(1-x) I'm sure you've seen it, we can see that the sequence we want\r
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\n" ); document.write( "\n" ); document.write( "where is given by\r
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\n" ); document.write( "\n" ); document.write( "Using this and the fact we want and copies of this sequence we get the general formula (lots of tidying up)\r
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\n" ); document.write( "\n" ); document.write( "However, we haven't dealt with the n=odd case. If you try out a few examples you will note that when n is odd there is an extra term So we need to add this when n is odd. The easiest way to do this is with a function that is 1 for odd and 0 for even.\r
\n" ); document.write( "\n" ); document.write( "Adding gives the final answer of\r
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\n" ); document.write( "\n" ); document.write( "It's quite possible I've made a mistake, but I've checked it with a few cases and it works so I'm pretty confident.\r
\n" ); document.write( "\n" ); document.write( "Of course the geometric formula isn't valid for x=1, so neither is this. I'll let you solve that case your self - it's pretty simple though.\r
\n" ); document.write( "\n" ); document.write( "Hope that helps,
\n" ); document.write( "Kev
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