document.write( "Question 471286: Milly is two thirds as old as Marcia. Four years from now she will be at most five sevenths as old as Marcia. At least how old is Milly?\r
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Algebra.Com's Answer #323254 by ankor@dixie-net.com(22740)\"\" \"About 
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Milly is two thirds as old as Marcia.
\n" ); document.write( " Four years from now she will be at most five sevenths as old as Marcia.
\n" ); document.write( " At least how old is Milly?
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\n" ); document.write( "let mi = Milly's present age
\n" ); document.write( "let ma = Marcia's present age
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\n" ); document.write( "Write an equation for each statement:
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\n" ); document.write( "\"Milly is two thirds as old as Marcia.\"
\n" ); document.write( "mi = \"2%2F3\"ma
\n" ); document.write( ":
\n" ); document.write( "\" Four years from now she will be at most five sevenths as old as Marcia.
\n" ); document.write( "mi + 4 =< \"5%2F7\"(ma+4)
\n" ); document.write( "multiply both sides by 7
\n" ); document.write( "7(mi+4) =< 5(ma+4)
\n" ); document.write( "7mi + 28 =< 5ma + 20
\n" ); document.write( "7mi =< 5ma + 20 - 28
\n" ); document.write( "7mi =< 5ma - 8
\n" ); document.write( "Replace mi with \"2%2F3\"ma
\n" ); document.write( "7(\"2%2F3\"ma) =< 5ma - 8
\n" ); document.write( "multiply both sides by 3
\n" ); document.write( "14ma =< 15ma - 24
\n" ); document.write( "14 ma - 15ma =< - 24
\n" ); document.write( "-1ma =< -24
\n" ); document.write( "multiply both sides by -1, this reverses the inequality sign
\n" ); document.write( "ma => 24
\n" ); document.write( "then
\n" ); document.write( "mi => \"2%2F3\"*24
\n" ); document.write( "mi => 16 \r
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