document.write( "Question 471286:  Milly is two thirds as old as Marcia.  Four years from now she will be at most five sevenths as old as Marcia.  At least how old is Milly?\r
\n" );
document.write( "\n" );
document.write( "This question needs to be resolved in inequalities. \n" );
document.write( "
Algebra.Com's Answer #323254 by ankor@dixie-net.com(22740)    You can put this solution on YOUR website! Milly is two thirds as old as Marcia. \n" ); document.write( " Four years from now she will be at most five sevenths as old as Marcia. \n" ); document.write( " At least how old is Milly? \n" ); document.write( ": \n" ); document.write( "let mi = Milly's present age \n" ); document.write( "let ma = Marcia's present age \n" ); document.write( ": \n" ); document.write( "Write an equation for each statement: \n" ); document.write( ": \n" ); document.write( "\"Milly is two thirds as old as Marcia.\" \n" ); document.write( "mi = \n" ); document.write( ": \n" ); document.write( "\" Four years from now she will be at most five sevenths as old as Marcia. \n" ); document.write( "mi + 4 =< \n" ); document.write( "multiply both sides by 7 \n" ); document.write( "7(mi+4) =< 5(ma+4) \n" ); document.write( "7mi + 28 =< 5ma + 20 \n" ); document.write( "7mi =< 5ma + 20 - 28 \n" ); document.write( "7mi =< 5ma - 8 \n" ); document.write( "Replace mi with \n" ); document.write( "7( \n" ); document.write( "multiply both sides by 3 \n" ); document.write( "14ma =< 15ma - 24 \n" ); document.write( "14 ma - 15ma =< - 24 \n" ); document.write( "-1ma =< -24 \n" ); document.write( "multiply both sides by -1, this reverses the inequality sign \n" ); document.write( "ma => 24 \n" ); document.write( "then \n" ); document.write( "mi => \n" ); document.write( "mi => 16 \r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "  |