document.write( "Question 471151: The number of cell phone minutes used by high school seniors follows a normal distribution with a mean of 500 and a standard deviation of 50. What is the probability that a student uses fewer than 600 minutes? \n" ); document.write( "

Algebra.Com's Answer #323169 by ewatrrr(24785) $\"\"$ $\"About$

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document.write( "Hi,
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document.write( "Note: P(z ≥ 2) = .0228  (Table,calculators, etc) Excel: NORMSDIST(-2) = .0228
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document.write( "mean of 500 and a standard deviation of 50
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document.write( "P( x < 600min) 
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document.write( " z = (600-500)/50 = 100/50 = 2   Note: P(z ≥ 2) = .0228
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document.write( "P( x < 600) = P(z < 2)=  1 - P(z ≥ 2) = 1 - .0228 = .9772    \n" );
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