document.write( "Question 471131: (log2x+logx)/(log2x-logx)=3 \n" ); document.write( "
Algebra.Com's Answer #323144 by nerdybill(7384)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "(log2x+logx)/(log2x-logx)=3\r \n" ); document.write( "\n" ); document.write( "(log2x+logx)-(log2x-logx)=3\r \n" ); document.write( "\n" ); document.write( "log2x+logx-log2x+logx=3\r \n" ); document.write( "\n" ); document.write( "logx+logx=3\r \n" ); document.write( "\n" ); document.write( "2logx=3\r \n" ); document.write( "\n" ); document.write( "logx=3/2\r \n" ); document.write( "\n" ); document.write( "x = 10^(3/2)\r \n" ); document.write( "\n" ); document.write( "x = 31.623 \n" ); document.write( " \n" ); document.write( " |