document.write( "Question 471131: (log2x+logx)/(log2x-logx)=3 \n" ); document.write( "
Algebra.Com's Answer #323144 by nerdybill(7384)\"\" \"About 
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\n" ); document.write( "(log2x+logx)/(log2x-logx)=3\r
\n" ); document.write( "\n" ); document.write( "(log2x+logx)-(log2x-logx)=3\r
\n" ); document.write( "\n" ); document.write( "log2x+logx-log2x+logx=3\r
\n" ); document.write( "\n" ); document.write( "logx+logx=3\r
\n" ); document.write( "\n" ); document.write( "2logx=3\r
\n" ); document.write( "\n" ); document.write( "logx=3/2\r
\n" ); document.write( "\n" ); document.write( "x = 10^(3/2)\r
\n" ); document.write( "\n" ); document.write( "x = 31.623
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