document.write( "Question 471131: (log2x+logx)/(log2x-logx)=3 \n" ); document.write( "

Algebra.Com's Answer #323142 by Alan3354(69443) $\"\"$ $\"About$

You can put this solution on YOUR website!
(log2x+logx)/(log2x-logx)=3
\n" ); document.write( " $\"log%282x%5E2%29%2Flog%282%29+=+3\"$
\n" ); document.write( " $\"log%282x%5E2%29+=+3log%282%29+=+log%282%5E3%29+=+log%288%29\"$
\n" ); document.write( " $\"2x%5E2+=+8\"$
\n" ); document.write( "x = 2
\n" ); document.write( "-----
\n" ); document.write( "x = -2 is rejected due to the logs
\n" ); document.write( " \n" ); document.write( "

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