document.write( "Question 470631: A cylinderical can is designed to hold a volume of 1000 cm3. \r
\n" ); document.write( "\n" ); document.write( "If the radius is increased by 25%, what is the corresponding decrease in height so the volume is still 1000 cm3? \r
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Algebra.Com's Answer #323133 by poliphob3.14(115)\"\" \"About 
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When r is increased by 25% it becomes \"%28125%2F100%29%2Ar\" and the volume of the can \r
\n" ); document.write( "\n" ); document.write( "changed to \"%28125%2F100%29%5E2\".\r
\n" ); document.write( "\n" ); document.write( "When h is decreased by x% it becomes \"%28100-x%29%2F100%2Ah\". Since the volume of the \r
\n" ); document.write( "\n" ); document.write( "can does not change we write the equation:\r
\n" ); document.write( "\n" ); document.write( "\"%28100%2F125%29%5E2=%28100-x%29%2F100\" solving this equation we get:\r
\n" ); document.write( "\n" ); document.write( "\"%2810000%2F125%5E2%29%2A100=100-x\"<=>\"x=100-%281000000%2F125%5E2%29\"<=>\"x=36\"\r
\n" ); document.write( "\n" ); document.write( "Answer:The height is decreased by 36%.
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