document.write( "Question 470747: 9x^2 – 25y^2 + 150y – 450 = 0
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document.write( "Find the center, vertices, foci, and asymptotes of the hyperbola \n" );
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Algebra.Com's Answer #323131 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! 9x^2 – 25y^2 + 150y – 450 = 0 \n" ); document.write( "Find the center, vertices, foci, and asymptotes of the hyperbola \n" ); document.write( "** \n" ); document.write( "9x^2 – 25y^2 + 150y – 450 = 0 \n" ); document.write( "9x^2 – 25y^2 + 150y = 450 \n" ); document.write( "9x^2-25(y^2+6y+9)=450-225=225 \n" ); document.write( "9x^2-25(y+9)^2=225 \n" ); document.write( "x^2/25-(y+9)^2/9=1 \n" ); document.write( "This is a hyperbola with horizontal transverse axis, opens sideways. \n" ); document.write( "Standard form: (x-h)^2/a^2-(y-k)^2/b^2=1 \n" ); document.write( "Center: (0,-9) \n" ); document.write( "a^2=25 \n" ); document.write( "a=5 \n" ); document.write( "length of transverse axis=2a=10 \n" ); document.write( "vertices: (0±5,-9) \n" ); document.write( ".. \n" ); document.write( "b^2=9 \n" ); document.write( "b=3 \n" ); document.write( "length of conjugate axis=2b=6 \n" ); document.write( ".. \n" ); document.write( "c^2=a^2+b^2=25+9=34 \n" ); document.write( "c=√34 \n" ); document.write( "Foci: (0±√34,-9) \n" ); document.write( ".. \n" ); document.write( "Asymptotes: \n" ); document.write( "slope, m=±b/a=±3/5 \n" ); document.write( "y= ±mx+b \n" ); document.write( "b=y-intercept=-9 (at center) \n" ); document.write( "Equation of asymptotes: \n" ); document.write( "y=±3x/5-9\r \n" ); document.write( "\n" ); document.write( "see graph below as a visual check on answers.\r \n" ); document.write( "\n" ); document.write( ".. \n" ); document.write( "y=±(9x^2/25-9)^.5-9 \n" ); document.write( " |