document.write( "Question 471064: a man is 4-times as old as her daughter , After 16-years , he will be twice as old as her daughter find the daughters age \n" ); document.write( "
Algebra.Com's Answer #323116 by algebrahouse.com(1659)![]() ![]() You can put this solution on YOUR website! x = daughter's age now \n" ); document.write( "4x = man's age now {man is 4 times as old as daughter}\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x + 16 = daughter in 16 years \n" ); document.write( "4x + 16 = man in 16 years\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "4x + 16 = 2(x + 16) {after 16 years, he will be twice as old as her} \n" ); document.write( "4x + 16 = 2x + 32 {used distributive property} \n" ); document.write( "4x = 2x + 16 {subtracted 16 from both sides} \n" ); document.write( "2x = 16 {subtracted 2x from both sides} \n" ); document.write( "x = 8 {divided both sides by 2} \n" ); document.write( "4x = 32 {substituted 8, in for x, into 4x}\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "daughter is 8 \n" ); document.write( " For more help from me, visit: www.algebrahouse.com \n" ); document.write( " |