document.write( "Question 471019: Take out the GCF:\r
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document.write( "13x to the 2nd yz plus 169xy to the 2nd z to the 2nd minus 39xyz to the 3rd \n" );
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Algebra.Com's Answer #323105 by algebrahouse.com(1659)![]() ![]() You can put this solution on YOUR website! 13x²yz + 169xy²z² - 39xyz²\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "GCF of 13, 169, and 39.....is 13 \n" ); document.write( "GCF of x², x, and x........is x {when choosing GCF of same variables, choose smallest exponent} \n" ); document.write( "GCF of y, y² and y........is y \n" ); document.write( "GCF of z, z², and z³......is z\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "GCF is 13xyz\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "= 13xyz(x + 13yz - 3z²) {factored out the GCF by dividing each term by it} \n" ); document.write( " For more help from me, visit: www.algebrahouse.com \n" ); document.write( " |