document.write( "Question 471017: Factor completely: 200x to the 3rd - 98xy to the second \n" ); document.write( "
Algebra.Com's Answer #323086 by jim_thompson5910(35256)\"\" \"About 
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Factor out the GCF 2x to get \"2x%28100x%5E2-49y%5E2%29\"\r
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\n" ); document.write( "\n" ); document.write( "Now use the difference of squares method to factor \"100x%5E2-49y%5E2\" to get \"%2810x%2B7y%29%2810x-7y%29\"\r
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\n" ); document.write( "\n" ); document.write( "So \"200x%5E3-98xy%5E2\" completely factors to \"2x%2810x%2B7y%29%2810x-7y%29\"\r
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\n" ); document.write( "\n" ); document.write( "In other words, \"200x%5E3-98xy%5E2=2x%2810x%2B7y%29%2810x-7y%29\"
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