document.write( "Question 471011: Jane is cooking beans and rice for dinner tonight. She has 3 cans of black beans, 1 can of red beans, and 4 cans of garbanzo beans in her cupboard. If she grabs a can of beans without looking at the label, what is the probability of her making black beans and rice for dinner? \n" ); document.write( "
Algebra.Com's Answer #323083 by jim_thompson5910(35256)![]() ![]() ![]() You can put this solution on YOUR website! Basically the question is about the beans (and not the rice)\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "P(Black Beans) = (# of cans of black beans)/(# of cans total)\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "P(Black Beans) = 3/8\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So the probability is 3/8, which in decimal form is 0.375 \n" ); document.write( " |