document.write( "Question 470978: h(t)= c-(d-4t)^2; At time t=0, an initial height of 6 feet. Until the ball hit the ground, its height in feet after t seconds was given by the function h (at the beginning of problem), in which c and d are positive constants. If the ball reached its maximum height of 106 feet at time t=2.5, what was the height in feet of the ball at t=1 ?\r
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document.write( "The answer is 70, but I do not understand how they came up with this answer....please help! \n" );
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Algebra.Com's Answer #323041 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! h(t)= c-(d-4t)^2; At time t=0, an initial height of 6 feet. Until the ball hit the ground, its height in feet after t seconds was given by the function h (at the beginning of problem), in which c and d are positive constants. If the ball reached its maximum height of 106 feet at time t=2.5, what was the height in feet of the ball at t=1 ? \n" ); document.write( "------------------- \n" ); document.write( "Solve for c & d \n" ); document.write( "------------------- \n" ); document.write( "h(t)= c-(d-4t)^2 \n" ); document.write( "h(0) = c - d^2 = 6 \n" ); document.write( "h(2.5) = c - (d - 10)^2 = 106 \n" ); document.write( "----------------------- \n" ); document.write( "c - d^2 = 6 \n" ); document.write( "c = d^2 + 6 \n" ); document.write( "-------------- \n" ); document.write( "c - (d - 10)^2 = 106 \n" ); document.write( "c - d^2 + 20d - 100 = 106 \n" ); document.write( "Sub for c \n" ); document.write( "d^2+6 - d^2 + 20d = 206 \n" ); document.write( "20d = 200 \n" ); document.write( "d = 10 \n" ); document.write( "-------- \n" ); document.write( "c = 106 \n" ); document.write( "------------- \n" ); document.write( "h(t) = 106 - (10 - 4t)^2 \n" ); document.write( "h(1) = 106 - 6^2 \n" ); document.write( "h(1) = 70 \n" ); document.write( " \n" ); document.write( " |