document.write( "Question 48775: Three consecutive even integers are such that the square of the third is 76 more than the square of the second. Find the three integers. \n" ); document.write( "

Algebra.Com's Answer #32304 by Nate(3500) $\"\"$ $\"About$

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First Integer: i
\n" ); document.write( "Second Integer: i + 2
\n" ); document.write( "Third Integer: i + 2 + 2 = i + 4
\n" ); document.write( " $\"%28i+%2B+4%29%5E2+=+76+%2B+%28i+%2B+2%29%5E2\"$
\n" ); document.write( " $\"i%5E2+%2B+8i+%2B+16+=+76+%2B+i%5E2+%2B+4i+%2B+4\"$
\n" ); document.write( " $\"i%5E2+-+i%5E2+%2B+8i+%2B+16+=+76+%2B+i%5E2+-+i%5E2+%2B+4i+%2B+4\"$
\n" ); document.write( " $\"8i+%2B+16+=+76+%2B+4i+%2B+4\"$
\n" ); document.write( " $\"4i+=+64\"$
\n" ); document.write( " $\"i+=+16\"$
\n" ); document.write( "First Integer: i = 16
\n" ); document.write( "Second Integer: i + 2 = 18
\n" ); document.write( "Third Integer: i + 4 = 20 \n" ); document.write( "

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