document.write( "Question 470920: write a system of linear equation whose solution gives the number of each type of room rented. when ten rooms are rented at the rates of $80 and $120 pernight. The total collected of the 10 rooms is $920. \n" ); document.write( "
Algebra.Com's Answer #323028 by ptaylor(2198)\"\" \"About 
You can put this solution on YOUR website!
Let x=number of rooms rented at $80/night; total collected from these rooms=$80x
\n" ); document.write( "And let y=number of rooms rented at $120/night; total collected=$120y
\n" ); document.write( "Now we are told that:
\n" ); document.write( "$80x+$120y=$920--------------------eq1
\n" ); document.write( "And we are also told that:
\n" ); document.write( "x+y=10-------------------eq2\r
\n" ); document.write( "\n" ); document.write( "We can solve these:
\n" ); document.write( "First divide each term in eq1 by 40 and we get:
\n" ); document.write( "2x+3y=23 ($ understood)----eq1a
\n" ); document.write( "Multiply each term in eq2 by 2 and subtract it from eq1a and we get:
\n" ); document.write( "y=3 ----number of $120/night rooms
\n" ); document.write( "substitute y=3 into eq2 and we have x=7----number at $80/nite\r
\n" ); document.write( "\n" ); document.write( "CK
\n" ); document.write( "3*$120+7*80=$920
\n" ); document.write( "$360+$560=$920
\n" ); document.write( "$920=$920\r
\n" ); document.write( "\n" ); document.write( "Hope this helps-----ptaylor\r
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