document.write( "Question 470909: How many liters of 50% acid must be mixed with 20% acid to get 10 liters of a 30% mixture? \n" ); document.write( "

Algebra.Com's Answer #322994 by ewatrrr(24785) $\"\"$ $\"About$

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document.write( "Hi,
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document.write( "get 10 liters 
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document.write( "Let x and (10L-x) represent the amounts of the 50% and 20% solutions respectively
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document.write( "Mixing
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document.write( "  .5x + .2(10L-x) = .30*10L
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document.write( "        .3x = .28*10L
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document.write( "          x = 9 1/3L of 50% and 2/3L of the 20% need to be mixed
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